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Math Challenge I-C Handout 4
I don't understand 4.30. Can anyone help me?
Question 4.30:
Dylan dives from a platform that is 4040 feet high. Dylans mom wants to take a picture right when Dylan is at the same heigh as her. Dylan's height above the water after tt seconds is h(t)=−16t2+8t+40h(t)=−16t2+8t+40. If Dylan's mom is sitting 1010feet above the water, how much time will pass before his mom takes the picture?
Can anyone at least give me a hint?
The problem gives us an equation for Dylan's height at time $t$: $h(t)=−16t^2+8t+40$ (measured in feet). We know that Dylan's mom wants to take a picture when his height is $10$ feet (because that is the height she is sitting). Therefore we should be able to use the equation to determine when Dylan is at $10$ feet.
Hope this helps!
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