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Calculus BC- antideriv of functions with multiplicative terms

 
 
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Re: Calculus BC- antideriv of functions with multiplicative terms
WangDr. Kevin - 2022年08月7日 Sunday 15:09
 

For this type of questions you can try substitution method: Let $u=x^2+1$, and then $du=2xdx$, and go from there.