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MCIV 58.10

 
 
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MCIV 58.10
by Kevin Song - Saturday, 10 February 2024, 8:49 PM
 

Hi, for this problem I do not understand why we chose that there exists a row with more than 10 1's and more than 10 -1's. Is this arbitrary or is it related somehow to the ratios we calculated earlier?

 
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Re: MCIV 58.10
by Dr. Kevin Wang - Tuesday, 13 February 2024, 10:58 PM
 

The number is pretty arbitrary.  The problem occurred in 1980, so it contained the numbers 1980.  But the actual result requires a size that is much smaller.

 
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