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Math Challenge II-B: Q3.16

 
 
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Math Challenge II-B: Q3.16
by CLAIRE SUN - Friday, 5 October 2018, 2:13 PM
 

The first two answer choices of this question happen to be the same. 

 
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Re: Math Challenge II-B: Q3.16
by David Reynoso - Monday, 8 October 2018, 9:29 AM
 

Thanks for letting us know, Claire!

Answer choice (B) should be $\displaystyle \frac{1-\sec(\theta)}{1+\sec(\theta)}$. It should be displaying correctly now.

 
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