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Math Challenge II-B: Q3.16

 
 
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Math Challenge II-B: Q3.16
SUNCLAIRE - 2018年10月5日 Friday 14:13
 

The first two answer choices of this question happen to be the same. 

 
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Re: Math Challenge II-B: Q3.16
ReynosoDavid - 2018年10月8日 Monday 09:29
 

Thanks for letting us know, Claire!

Answer choice (B) should be $\displaystyle \frac{1-\sec(\theta)}{1+\sec(\theta)}$. It should be displaying correctly now.

 
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