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MC II B: I am not sure how to start questions 4.25, 4.26, and 4.30...

 
 
SUNCLAIRE的头像
MC II B: I am not sure how to start questions 4.25, 4.26, and 4.30...
SUNCLAIRE - 2018年10月8日 Monday 15:34
 

Could you possibly provide some minor hints to start the problems? Thank you.

 
ReynosoDavid的头像
Re: MC II B: I am not sure how to start questions 4.25, 4.26, and 4.30...
ReynosoDavid - 2018年10月9日 Tuesday 11:42
 

For 25, try factoring (remember $\cos^n(x)$ means $(\cos(x))^n$) and see if you then spot a way to use trigonometric identities you've learned so far (like $\sin^2(x) + \cos^2(x) = 1$, $\sin(2x) = 2\sin(x)\cos(x)$, etc.).

For 26, recall that supplementary angles have the same $\sin$, so of $\alpha + \beta = 180^\circ$, then $\sin(\alpha) = \sin(\beta)$.

For 30, try using the result from example 4.10: in a triangle $ABC$ with sides $a,b,c$ we have $$\dfrac{a-b}{a+b} = \tan\left(\dfrac{A-B}{2}\right)\tan\left(\dfrac{C}{2}\right).$$

Let us know if these helped, or if you need additional hints.

SUNCLAIRE的头像
Re: MC II B: I am not sure how to start questions 4.25, 4.26, and 4.30...
SUNCLAIRE - 2018年10月9日 Tuesday 17:30
 

Unfortunately, I am still stuck and may require additional hints. 

ReynosoDavid的头像
Re: MC II B: I am not sure how to start questions 4.25, 4.26, and 4.30...
ReynosoDavid - 2018年10月11日 Thursday 11:09
 

Can you tell us what have you tried so far?

SUNCLAIRE的头像
Re: MC II B: I am not sure how to start questions 4.25, 4.26, and 4.30...
SUNCLAIRE - 2018年10月11日 Thursday 12:14
 

Yes. I'm stuck at the trigonometric identities because I can't seem to find any that satisfy and I have tried to add the two arcsines of the sines provided but it is not seeming to work out cleanly. Finally, I'm not sure how the third hint applies to the problem. 

ReynosoDavid的头像
Re: MC II B: I am not sure how to start questions 4.25, 4.26, and 4.30...
ReynosoDavid - 2018年10月11日 Thursday 15:14
 

For 25, after factoring, try using the double angle trigonometric identities.

For 30, since angles do not change when we have similar triangles, it is safe to assume $c=1$, and so $b = 2+\sqrt{3}$. Using the previous hint you can calculate $\tan\left(\dfrac{B-C}{2}\right)$, and then use that value of $\tan$ to find what $B-C$ is. 

SUNCLAIRE的头像
Re: MC II B: I am not sure how to start questions 4.25, 4.26, and 4.30...
SUNCLAIRE - 2018年10月11日 Thursday 15:40
 

Thank you!