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MC-II-A Question number 7.27 and 7.28
I'm a bit confused on how to prove this , and I can't figure out where t start
On 7.27 proceed similarly to 7.5. Try to write $\angle APB$ as the difference of two inscribed angles that open precisely to the arcs $\widehat{AB}$ and $\widehat{CD}$.
On 7.28 try finding some equilateral triangles in your diagram. (Extra hint: Since both cords $AB$ and $CD$ have the same length, what can you say about $AE$, $BE$, $CE$ and $DE$?)
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