Online Course Discussion Forum

week 5

 
 
Picture of Amy T
week 5
by Amy T - Sunday, 31 March 2019, 7:10 PM
 

Find all six digit numbers consisting entirely of 00's and 11's that are divisible by 1212.

 
Picture of David Reynoso
Re: week 5
by David Reynoso - Monday, 1 April 2019, 10:38 AM
 

$12 = 2^2 \times 3$, so the numbers you are looking for must be divisible by $2^2 = 4$ and by $3$.

Use the rules for divisibility by $3$ and $4$ to find conditions for the digits of your number(s).