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Math Challenge II-A Number Theory

 
 
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Re: Math Challenge II-A Number Theory
by Areteem Professor - Monday, July 15, 2019, 12:21 PM
 

Please note that $$2016 = 22\times 91 + 14,$$ so $$2^{2016} = \left(2^{22}\right)^{91}\cdot 2^{14}.$$ You can carry out the rest and verify what the answer actually is.