My apologies, it seems I was looking at chapter 5 of algebra.

Since we want the number to have exactly $12$ divisors, it is a multiple of $3$ distinct prime numbers,  and $12 = (1+1)(1+1)(2+1)$, the number must be of the form $2^a \times 3^b \times 5^c$, where two of the exponents are $1$ and one of the exponents is $2$.

What numbers can be obtain by doing this?