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Math Challenge II-A Combinatorics

 
 
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Re: Math Challenge II-A Combinatorics
ProfessorAreteem - 2019年09月4日 Wednesday 13:21
 

Here the problem states that we have "two different committees" which is our clue that the two groups are different.

It is good to understand how the problem would be different if we wanted two indistinguishable groups instead: the answer would just be the same except divided by $2! = 2$.