Online Course Discussion Forum

Math Challenge II-A Combinatorics

 
 
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Re: Math Challenge II-A Combinatorics
by Areteem Professor - Wednesday, 4 September 2019, 1:21 PM
 

Here the problem states that we have "two different committees" which is our clue that the two groups are different.

It is good to understand how the problem would be different if we wanted two indistinguishable groups instead: the answer would just be the same except divided by $2! = 2$.