Online Course Discussion Forum

Combinatorics Complex number

 
 
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Re: Combinatorics Complex number
by Dr. Kevin Wang - Monday, 28 October 2019, 10:05 PM
 

If $a_k$ is $2$ or $4$, $i^{a_k}$ is already a real number.  Since $i^3=-i^1$, the sum is a real number if $1$ and $3$ are paired up.  Thus we can count the following cases on the number of $(1,3)$  pairs: $0$ pairs, $1$ pair, $2$ pairs, $3$ pairs, and $4$ pairs.  Each case is quite straight forward.