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Math Challenge II-A Combinatorics

 
 
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Math Challenge II-A Combinatorics
by Neo Liang - Thursday, 28 November 2019, 3:52 PM
 

Lecture 9, Problem 9.26

Shouldn't the denominator in the last fraction in the answer be 216, because $6^3=216$?

 
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Re: Math Challenge II-A Combinatorics
by Areteem Professor - Monday, 2 December 2019, 11:45 AM
 

The last fraction represents the probability of getting a sum of $8$ when the dice is rolled four times, so its denominator is $6^4 = 1296$.

 
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