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Math Challenge II-A Combinatorics

 
 
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Math Challenge II-A Combinatorics
LiangNeo - 2019年11月28日 Thursday 15:52
 

Lecture 9, Problem 9.26

Shouldn't the denominator in the last fraction in the answer be 216, because $6^3=216$?

 
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Re: Math Challenge II-A Combinatorics
ProfessorAreteem - 2019年12月2日 Monday 11:45
 

The last fraction represents the probability of getting a sum of $8$ when the dice is rolled four times, so its denominator is $6^4 = 1296$.

 
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