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1025867@etusd.org

 
 
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Re: 1025867@etusd.org
by Areteem Professor - Friday, 20 March 2020, 10:37 AM
 

Both $(2^{12} -1) \pmod{13}$ and $2^{12} - 1 \pmod{13}$ mean exactly the same thing. The idea is to find an integer from $0, 1, \dots, 12$, say $a$,  so that $2^{12}-1 \equiv a \pmod{13}$.