Using the quadratic formula, the solutions to the equation $ax^2 + bx + c = 0$ are $$\begin{aligned} x_1 &= \dfrac{-b + \sqrt{b^2-4ac}}{2a} \\ x_2 &= \dfrac{-b - \sqrt{b^2-4ac}}{2a}, \\ \end{aligned}$$ and the solutions to the equation $y^2 +by + ac = 0$ are $$\begin{aligned} y_1 &= \dfrac{-b + \sqrt{b^2 -4ac}}{2} \\ y_2 &= \dfrac{-b - \sqrt{b^2 -4ac}}{2}. \end{aligned}\\$$

Note the only difference between the two is the denominator. So $x_1 = \dfrac{y_1}{a}$ and $x_2 = \dfrac{y_2}{a}$. Which is answer choice C.