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Math Challenge II-B 7.27 Algebra
Math Challenge II-B 7.27 Algebra
I'm kind of confused as how to factor the discriminant of this quadratic: $x^2+2(1+a)x+(3a^2+4ab+4b^2+2)=0$. I got a really messy equation out of it.
I'm kind of confused as how to factor the discriminant of this quadratic: $x^2+2(1+a)x+(3a^2+4ab+4b^2+2)=0$. I got a really messy equation out of it.
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