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Math Challenge III 3.10 Algebra

 
 
luoRaymond的头像
Math Challenge III 3.10 Algebra
luoRaymond - 2020年07月29日 Wednesday 11:09
 

I tried many things for this problem, like Simon's Favorite Factoring Trick which gave me $(x+1)(y+1)=6$ and $(x^3+1)(y^3+1)=18$ and substituting $u=x+y$ and $v=xy$ to get

$\begin{cases}  u(u^2-3v)+v^3=17 \\ u+v=5 \end{cases}$

Both didn't help that much however. Is there something that I'm missing?

 
WangDr. Kevin的头像
Re: Math Challenge III 3.10 Algebra
WangDr. Kevin - 2020年07月29日 Wednesday 22:25
 

SFFT does not help because this is not for integer solutions.

Your substitution does help. Write the first equation as $u^3- 3uv + v^3= 17$. This is as much hint as I need to give you. :)