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Math Challenge II-B Algebra Problem 8.25

 
 
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Re: Math Challenge II-B Algebra Problem 8.25
ProfessorAreteem - 2020年08月3日 Monday 12:58
 

Since $x = \sqrt{5-k}$ for a positive number $k \leq \sqrt{5}$, it must be true that $0 < x < \sqrt{5}$. This can help get rid of possible extraneous solutions.