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Blue Geometry P20

 
 
ZhangCharles的头像
Blue Geometry P20
ZhangCharles - 2021年01月5日 Tuesday 15:21
 
I have found cos(B/2) = ((a+c)^2 - b(b-a))/(2a)(b+c), and I am not sure how to proceed from here.


Any help would be appreciated!

 
ZhangCharles的头像
Re: Blue Geometry P20
ZhangCharles - 2021年01月6日 Wednesday 21:37
 

Note: this is for Winter Camp

LensmireJohn的头像
Re: Blue Geometry P20
LensmireJohn - 2021年01月16日 Saturday 14:09
 

Thanks for your patience here Charles!

Looks like you're on the right track. Few questions (as hints):

  1. What does Law of Cosines tell us about cos(B)?
  2. Can we turn this into an equation involving cos(B/2) using a trig. identity?

Combining this with your expression from above should give an equation you can solve for cos(B/2).

ZhangCharles的头像
Re: Blue Geometry P20
ZhangCharles - 2021年01月16日 Saturday 18:22
 
My work
ProfessorAreteem的头像
Re: Blue Geometry P20
ProfessorAreteem - 2021年01月26日 Tuesday 21:56
 

Did you see the post in here about this?