Online Course Discussion Forum
MC III Number Theory 1.14
Let me give the idea and a quick hint here. (Note: The course recording has the answer to the question I'll ask in the hint below.)
This problem is related to Bezout's Theorem:
- If gcd(a,b) = 1, then there exist m and n so that a*m + b*n = gcd(a,b).
In fact, it's exploring the converse that is relevant here:
- If there exist m and n so that a*m + b*n = k, then k is a multiple of gcd(a, b).
- Or really the special case of: if there exist m and n so that a*m + b*n = 1, then gcd(a,b) = 1.
Start first by making sure these make sense.
Now back to the problem: To show (a+b)/(c+d) is irreducible, we need to show gcd(a+b, c+d) = 1. This means we want to look for m and n so that (a+b)*m + (c+d)*n = 1. Hint: Nothing above has used the fact that ad-bc=1, so that is probably relevant here!
Hope this help!
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