Online Course Discussion Forum
Math Challenge 3. Chapter 5
I'm having trouble on 5.17. I tried rationalizing but that didn't really work. So I'm not sure if Im supposed to do some kind of substitution.\
5.20 and 5.23: I did similar things for both of these. I tried to get rid of denominators. For 5.20 I did a y substitution for x^2 but that didn't really work.
5.24: I'm not sure where to start.
This is for MC III Algebra in the AIME Intensive Prep Class.
Question 5.17: Solve the equation: \[ \frac{x-7}{\sqrt{x-3}+2} + \frac{x-5}{\sqrt{x-4}+1} = \sqrt{10}. \]
Rationalizing should work. Try again, and use the substitutions $u=\sqrt{x-3}$, $v=\sqrt{x-4}$. (After rationalizing the denominators, you don't really need the substitutions to solve it, but it is cleaner to use them.)
Question 5.20:\[ \frac{1}{x^2+1} +\frac{x^2+1}{x^2} = \frac{10}{3x}. \]
Try multiplying $x$ on both sides.
Question 5.23: \[ \frac{2x}{3} = \frac{x^2}{12}+\frac{3}{x^2}+\frac{4}{x}. \]
You can multiply $12$ on both sides and see what happens.
Question 5.24: Assume $a<30$ is an integer, and the equation (in $x$) $$\sqrt{2x-4}-\sqrt{x+a}=1$$ has exactly one integer root. Find all possible values for $a$.
There is not really a special trick for this one; you can clear the radicals first, and you get a quadratic equation in $x$, then apply the quadratic formula. Since there is one integer root, some analysis can be done with the root.
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