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Math Challenge II-A (AMC 10) Summer 2017 (Algebra)

 
 
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Math Challenge II-A (AMC 10) Summer 2017 (Algebra)
ZhangAndrew - 2017年06月10日 Saturday 19:29
 

How is problem 1.16 on quick response question solved. I don't get how it works with the "tip" of using 8 = 9-1. The problem is factor x^2-6x+8

 
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Re: Math Challenge II-A (AMC 10) Summer 2017 (Algebra)
ReynosoDavid - 2017年06月12日 Monday 15:27
 

Try changing that $8$ in $x^2-6x+8$ to $9-1$. Can you see something that can be factored easily using some of the terms?