Online Course Discussion Forum
Math Challenge II-A Combinatorics
It says that the answer is "We have . Thus, we need to solve a total of three times (once each for ). Thus there are different products.".
However, Shouldn't it be "5+3-1 choose 5" then quantity cubed, which is equal to the cube of 21 which is 9261? Because each exponent can have 5 different results, which are 0,1,2,3,4. There are five, not four numbers, between 0 to 4. Am I wrong or is the answer wrong?